next and current element in a collection

Asked Jun 23 '14 at 16:50

Active Jun 23 '14 at 16:50

Viewed 20 times

I've been wondering if I can make this code more pythonic

for i in xrange(len(my_list) - 1)):
    first = my_list[i]
    second = my_list[i + 1]

something like:

for first,second in foo(my_list):

In Scala I would use (my_list.tail, my_list).zipped

I'm looking for a solution that will NOT allocate extra memory like zip(my_list,my_list[1:])

asked Jun 23 '14 at 16:50

Lukasz Madon

`zip` does not allocate extra memory on Py3k – vaultah Jun 23 '14 at 16:51
@frostnational: this is Python 2; `xrange()` is used. – Martijn Pieters Jun 23 '14 at 16:51
@frostnational but slicing does, doesn't it? – Lukasz Madon Jun 23 '14 at 16:52
Oh sliding is the keyword to google it. Thx. – Lukasz Madon Jun 23 '14 at 16:53

0 Answers0