If String is not a Primitive datatype in Java and if Java does not support operator overloading then how is this possible
String x = "foo";
System.out.print( x + "bar");
It Prints foobar. How?!
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19Because the language designers accepted that operator overloading is useful, even though they wouldn't trust it to users. – Deduplicator Jun 26 '14 at 11:15
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@Deduplicator aptly said... – madteapot Jun 26 '14 at 11:15
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@Deduplicator - they could have accepted string[index] as well. :) – TheLostMind Jun 26 '14 at 11:17
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@TheLostMind: How often do you use `+` on strings and how often would you use `string[index]`. Not worth the hassle IMHO – gexicide Jun 26 '14 at 11:20
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@gexicide - For people who have come from C++ background, string.charAt() is ridiculously long to type ('ch'+ctrl+space isn't small either). I would prefer string[index] any day. – TheLostMind Jun 26 '14 at 11:21
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@TheLostMind: People coming from C++ will find a lot of things in Java ridiculously long to type ;). Typedefs for long generic classes would be nice for example, we can go on like this forever... – gexicide Jun 26 '14 at 11:24
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@gexicide - ya.. ya.. every labguage has its own advantages... :) – TheLostMind Jun 26 '14 at 11:25