PHP generate JSON code

Question

Model JSON: https://dl.dropboxusercontent.com/s/vjq9j5gwkbrly3y/data.json

How can I generate the above JSON using PHP, including the separate categories in to the above model?

I need help to separate the above categories for JSON. Do I have to do several selects?

Not sure what you mean by do i have to do several selects....as you're not mentioning MYSQL at all , youre asking how to generate JSON with php — Kylie, Jun 27 '14 at 22:01

Kylie · Answer 1 · 2014-06-27T22:00:08.130

Just build your arrays,

    $array = array("Restaurants"=>array(
      array("ID"=>23,"name"=>"test","example"=>"ex"),
      array("ID"=>23,"name"=>"test","example"=>"ex"),
      array("ID"=>23,"name"=>"test","example"=>"ex")
     ),
    "Categories"=>array(
      array("cat"=>"example","ex"=>"example"),
      array("cat"=>"example","ex"=>"example")
     )
     );

Then use json_encode

    echo json_encode($array);

EXAMPLE

PHP generate JSON code

1 Answers1