java using nextLine() in for loop ,

Question

Instead of printing out each statement and waiting for input it prints out both statements and waits for one input.

for(int i=0; i < size; i++)
{
    System.out.println("course: ");
    courses[i] = sc.nextLine();

    System.out.println("teacher: ");
    teachers[i] = sc.nextLine();
}

Output:

Enter number of classes: 2 course:

teacher:

possible duplicate of [Scanner issue when using nextLine after nextXXX](http://stackoverflow.com/questions/7056749/scanner-issue-when-using-nextline-after-nextxxx) — Piotr Praszmo, Jun 28 '14 at 20:21

score 1 · Accepted Answer · answered Jun 28 '14 at 20:19

1

The new line has been consumed be courses[i] = sc.nextLine(); so that is why it skipped

solution:

add nextLine before the forLoop:

sc.nextLine(); //will consume the new line
for(int i=0; i < size; i++){

answered Jun 28 '14 at 20:19

Rod_Algonquin

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thank you very much it works, so if i understood correctly the new line that is caused by println() is what is being consumed. – Th3OnlyOn3 Jun 28 '14 at 20:48
@user3786610 no it is the nextInt(). because when you input 2 it will just consumed the 2 not the newLine after it. – Rod_Algonquin Jun 28 '14 at 20:50
yes that makes more since ty, – Th3OnlyOn3 Jun 28 '14 at 20:54

java using nextLine() in for loop ,

1 Answers1