PHP substring not working for intergers

Question

I am trying to extract part of a number using sustr() but the following is not working:

$num = 012014;

echo substr($num, 0,2);

returns 51

BUT

$num = '012014';

echo substr($num, 0,2);

returns 01

I want it to return 01 can someone help me

Well, you can't write ``$num = 012014;`` to begin with. Did you skip your math classes? — Frantisek, Jun 30 '14 at 08:27
`012014` is treated as an octal number. The value of `$num` is 5132. — Jim, Jun 30 '14 at 08:30
`$num = 012014` equals to `$num = 5132`. [php integer](http://www.php.net/manual/en/language.types.integer.php) — sectus, Jun 30 '14 at 08:30
Thanks Rikesh. It has worked the problem was putting a o at the beggining of a number. Thanks everyone — user3789498, Jun 30 '14 at 08:37

score 0 · Accepted Answer · answered Jun 30 '14 at 08:31

0

Is is not a normal number, when it's prepended with a zero (0). Then it's an octal number

If you treat $num as a string, it'll work.

$num = '012014';
echo substr($num, 0,2);

answered Jun 30 '14 at 08:31

Trolley

score 0 · Answer 2 · edited Jun 30 '14 at 08:55

0

I guess you must declare the variable as string like this.

$num = '012014'; 
echo substr( (string)$num, 0, 2 );

edited Jun 30 '14 at 08:55

Tiny

answered Jun 30 '14 at 08:33

PaulusCh

1

No need for the cast in the `substr` call – Elias Van Ootegem Jun 30 '14 at 08:34

score -1 · Answer 3 · answered Jun 30 '14 at 08:32

-1

Ooops I didn't notice the leading zero. You should just define $num as a string

$num = '0123';

answered Jun 30 '14 at 08:32

Samuil Banti

score -1 · Answer 4 · answered Jun 30 '14 at 08:35

-1

Please try this

$num = 123424;
$num = (string)$num;

echo substr($num, 0,2);

answered Jun 30 '14 at 08:35

ahmad05

This wont work with the original number: http://codepad.org/z2qAPMZb – Jim Jun 30 '14 at 08:40
i have tested code on this " http://writecodeonline.com/php/" and it works – ahmad05 Jun 30 '14 at 10:48
Have you tested using `$num = 012014;`? Your code will not work for numbers beginning with a `0` because PHP will treat them as an octal number. – Jim Jun 30 '14 at 11:49

4 Answers4