Split a list Python

Question

Hello I have a list containing one string that I need to split in two on the comma:

value = ['Red, Orange']

I split using :

value = value[0].split(", ")

But I get :

value[0] = "Red"

and

value[1:] = ["Orange"]

why is value[1:] a list? What can I do to get

value[1:] = "Orange"

Thanks

What made you use a ":" for the second one but not the first? — Byron Coetsee, Jul 01 '14 at 08:25
See here for info on slicing: http://stackoverflow.com/questions/509211/pythons-slice-notation — jpmc26, Jul 01 '14 at 08:30

score 0 · Accepted Answer · answered Jul 01 '14 at 08:21

0

You simply do:

value[1]

without the :. This indicates to python that you are getting an element at a specific index and not a portion of the string from index 1 to the last element.

value[0] will contain "Red"

and

value[1] will contain "Orange"

What you are doing with the [:] is known as list slicing. Perhaps you should read about it so that it is clear.

answered Jul 01 '14 at 08:21

sshashank124

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thanks but value[1] gives me the error : `list index out of range` – salamey Jul 01 '14 at 08:33
@salamey, Well. After you do the split. – sshashank124 Jul 01 '14 at 08:35

score -1 · Answer 2 · answered Jul 01 '14 at 08:36

-1

You may write this:

value = [x for x in value[0].split(", ")]

It's called list comprehension and it will work for arbitrary number of words in value[0]

answered Jul 01 '14 at 08:36

evocatus

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-1, a comprehension is totally unnecessary since split already gives a list. Also this doesn't answer the question – erlc Jul 01 '14 at 09:01

Split a list Python

2 Answers2