this is example what i'm looking for.
Example:
Input: ['234','34','22','7','99']
0:0
1:0
2:3
3:2
4:2
5:0
6:0
7:1
8:0
9:2
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Andy
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SSR.P.S.das
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2Have you tried yourself? – Germano Jul 02 '14 at 16:37
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http://mattgemmell.com/what-have-you-tried/ – Andrew Gorcester Jul 02 '14 at 16:37
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http://stackoverflow.com/questions/4664850/find-all-occurrences-of-a-substring-in-python – Anderson Green Jul 02 '14 at 16:38
1 Answers
1
joined joins all the chars into one string "2343422799"
Then we loop through the digits 0-9 and use the count method to see how many times each digit appears in the string and print the digit and the count using string formatting.
l=['234','34','22','7','99']
joined="".join(l) # joins all the chars into one string "2343422799"
for ch in range(10): # go through digits from 0-9
print "{}:{}".format(ch,joined.count(str(ch)))
0:0
1:0
2:3
3:2
4:2
5:0
6:0
7:1
8:0
9:2
Padraic Cunningham
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Please add some explanation. Pure code is good, but code + explanation is much better – Barranka Jul 02 '14 at 17:08