Extract section of xml from result of curl command on Linux

Question

I am issuing the following command:

curl http://localhost:8082/some-url

Which returns xml that looks similar to this:

<?xml version="1.0" encoding="UTF-8"?><user><dateCreated>1</dateCreated><dateLastModified>1</dateLastModified><id>1</id><disabled>false</disabled><firstName></firstName><lastName></lastName></user>

What is the easiest way to extract an xml element from the response, e.g. the element "true"?

Note, I want the complete opening tag, content, and closing tag (and the content may also be empty.

Thanks

http://stackoverflow.com/questions/487213/whats-the-best-xml-parser-for-perl — hmatt1, Jul 03 '14 at 14:36

score 4 · Answer 1 · answered Jul 03 '14 at 15:04

4

Using xml_grep, which comes with XML::Twig, you can do curl http://localhost:8082/some-url | xml_grep --nowrap disabled (I assumed you wanted the content of the disabled element, I don't see any true element in your data)

answered Jul 03 '14 at 15:04

mirod

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Kokkie · Accepted Answer · 2014-07-03T15:17:03.140

3

Would xmllint be an option for you as well?

$ curl -s http://localhost:8082/some-url | xmllint --xpath '//user/disabled' -

edited Jul 03 '14 at 15:17

answered Jul 03 '14 at 14:47

Kokkie

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score 0 · Answer 3 · answered Jul 03 '14 at 15:58

0

Or the same with xsh (http://xsh.sourceforge.net/):

$ curl -s http://localhost:8082/some-url | xsh -q -I - -C 'ls //user/disabled/text()'

answered Jul 03 '14 at 15:58

buff

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score 0 · Answer 4 · answered Jan 01 '20 at 21:52

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The classic solution is to use xmlstarlet, for example for an RSS feed:

URL="https://feeds.feedburner.com/TEDenEspanol"
curl -s $URL | xmlstarlet sel -t -v 'rss/channel/title'

answered Jan 01 '20 at 21:52

Pablo Bianchi

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Extract section of xml from result of curl command on Linux

4 Answers4