3

I want to know why we cant use the <, <=, > or >= relational operators on Strings.

import java.util.*;
public class Coffee{
    public static void main(String args[]){
        String s1="Cat";
        String s2="Dog";
        System.out.println(s1 < s2);
    }
}

gives the error "operator < cannot be applied to java.lang.String".

Why can't Java compare strings like this: C < D?

Stephen C
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user2899676
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    Because what sense would "The UnderTaker" > "Ray Mysterio" make to a person who has never watched WWE?. Java doesn't implicitly take the int values of characters and compare..( unlike in C++ where Operators are overloaded.) – TheLostMind Jul 03 '14 at 14:43
  • Easy - because Java chose not to implement those operators to take String arguments. You do it using Comparator implementations. – duffymo Jul 03 '14 at 14:43
  • The behaviour of `>` etc. should be consistent with `compareTo`, so this is not the problem. – Erich Kitzmueller Jul 03 '14 at 15:02

4 Answers4

4

The simple answer is: because they weren't implemented. Java (unlike e.g. C/C++) does not rely on operator overloading, so you have to get the value of a String with length method and then compare the results with your < > <= >= operators.

Side note: Strings in Java also implement Comparable interface. It allows you to use compareTo method, which returns 0 if the argument is a strings are equal, a value less than 0 if the argument is greater than string which you run this method on; and a value greater than 0 if the argument is a string smaller than this string.

Side note 2: By "greater string" I mean lexicographically greater (alphabetically).

TheMP
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2

String is not a primitive data type like int and double are. Strings are objects.

For Strings, the relational operator, ==, only checks to see if the objects "point" to the same data in the heap.

For example,

String s1="Cat";
String s2= new String("Cat");

if(s1==s2)
System.out.println("They are the same");

The if statement WILL NOT execute. This is because after you created an instance of "Cat", you create another instance of "Cat," in the heap. The two variables do not "point" to the same data.

compareTo methods check to see if the actual data that the variables are allocated to in a heap are equal to each other, and is one of the many correct ways to see if two String objects are equal to each other.

I hope it helped, if my response is unclear, please do not hesitate to ask.

TriedMyBest
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  • This should be the accepted answer. I completely forgot that the equals operator(==) only did a pointer check; even for Strring(s). – user13947194 Aug 13 '22 at 20:47
0

If you really want to do this, use the compareTo result.

if ("a".compareTo("b") >= 0) {
    // do stuff
}

If you want to ignore case you can do:

if (String.CASE_INSENSITIVE_ORDER.compare("A", "b") <= 0) {
   // do stuff
}
lance-java
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0

Here's the right way: 

import java.util.*;
public class Coffee {
    public static void main(String args[]) {
        String s1="Cat";
        String s2="Dog";
        System.out.println(s1.compareTo(s2));
    }
}
duffymo
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