Convert from non pointer to pointer

Question

I have a function that looks something like

foo(object& obj) {

}

inside this function I need to call another function like this:

foo(object& obj) {
    bar(pointer to obj);
}

the bar function takes a pointer to the object as an argument. Could some help I can do convert from non pointer to pointer?

-1 because it's ridiculous to ask on SO about the basicest basics of the language. That's what C++ books are for. — Matteo Italia, Jul 03 '14 at 16:55
This is indeed a very basic programming question, but a legitimate one, and reasonably well formulated. There are no requirements on SO about the "level" of the question. I'm upvoting to put it back in the queue. — Kirk Roybal, Jul 03 '14 at 17:17

score 5 · Answer 1 · answered Jul 03 '14 at 16:48

5

That what & is for, the "address of" operator.

bar(&obj);

answered Jul 03 '14 at 16:48

David Schwartz

score 0 · Answer 2 · answered Jul 03 '14 at 16:48

0

Call bar with the address of obj:

bar(&obj);

answered Jul 03 '14 at 16:48

score 0 · Answer 3 · answered Jul 03 '14 at 16:51

0

Call as follows

bar(&obj);

answered Jul 03 '14 at 16:51

Can you add some additional context and explanation for why this is the answer? – Ryan Gates Jul 03 '14 at 17:20

3 Answers3