How to display a floating point result of a division of two integers?

Question

I have a problem with displaying and keeping any floating number or double or long or floating type this is the code :

int sd, n;
float d;    
d=n/sd.capacity();

cout << d.toFloat() << endl;
cout << n << " / " << sd.capacity() << " = " << d << endl;

In the output I have d equal to 0 everytime, sd.capacity() and n are never 0, so all the time n is lower than sd.capacity value, d = 0 but it should never 0. The variable d does not contain anything but 0.

`float` is a primitive, not an object. It has no `toFloat()` member function, or any other member functions! — uckelman, Jul 03 '14 at 19:51

score 0 · Accepted Answer · answered Jul 03 '14 at 19:09

0

int/int results into int. So this does a problem.

You need to have atleast one of the operands as float.

Since, you are telling that n always < than sd.capacity(), so n/sd.capacity() in int division always gives 0.

I suppose you should do,

d= (float)n / (float)sd.capacity();

Does this solve it?

answered Jul 03 '14 at 19:09

j809

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yeah done thank's a lot solved by this thank's d= (float)n / (float)sd.capacity(); – user3802999 Jul 03 '14 at 19:40
Glad to help :). But from next time try to search about your question, or else repeated questions often get downvoted badly. – j809 Jul 03 '14 at 19:45
You don't need to cast both `n` and `sd.capacity()` to `float`. The division will be floating point if at least one of them is a `float`. – uckelman Jul 03 '14 at 19:53
I have already mentioned it... – j809 Jul 03 '14 at 19:53

How to display a floating point result of a division of two integers?

1 Answers1