How do I have a random int from 1 to 6 using math.random() in java?

Question

I'm writing a method in java which relates to a die throw and I try to use the math.random() but i realized that 0 is included in the random integers involved. Additionally, I don't quite get the *7 part what does it mean?

I went to research from the Java API but it doesn't mention any bit about this or is it I am doing the wrong research? Thanks so much for reading!

public int dieThrow()
{
    int num = (int)(Math.random() *7); //returns an integer 
    return num;
}

This post might help http://stackoverflow.com/questions/363681/generating-random-integers-in-a-range-with-java — LordSquall, Jul 03 '14 at 20:26

score 3 · Answer 1 · answered Jul 03 '14 at 20:29

3

This is a pretty simple exercise. You observe that 0 is a possible outcome, so you simply + 1 to the result, like so:

public int throwDie()
{
    return (int)(Math.random() * 6) + 1;
}

answered Jul 03 '14 at 20:29

BlackBox

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How do I have a random int from 1 to 6 using math.random() in java?

1 Answers1