Variable not substituting value. What am I doing wrong?

Question

In the following code fragment, the value of $key (line 39) is not being substituted. Can someone suggest why?

The variable is receiving the correct value as I have debugged for that in line 37 and it is correct.

If I replace the variable with an integer then the code run correctly i.e. it opens the form and executes a query returning the expected records.

Why will the substitution not take place within php and what must I do for the substitution to take place?

Thanks in advance.

 37 //var_dump($key);
 38 //echo "<br>";
 39 header( 'Location: http://xx.x.80.94/ants/connie/allExhibitsForEvent.php?id=$key' );
 40 ?>

If anything this should have been closed as a typo. The duplicate question doesn't address single vs. double quoted strings. — , Jul 04 '14 at 03:38
I was going to VTC for that reason, but the reason also says 'is not helpful for future users' - this question likely is helpful. — sevenseacat, Jul 04 '14 at 03:40
This is a better duplicate question: http://stackoverflow.com/questions/18357786/single-quotes-and-double-quotes-in-php — , Jul 04 '14 at 03:40
no problem let me reopen .... btw i could not cast close again :( — NullPoiиteя, Jul 04 '14 at 03:42

score 2 · Answer 1 · answered Jul 04 '14 at 03:34

2

If you want string interpolation of variables, use double quotes:

header( "Location: http://xx.x.80.94/ants/connie/allExhibitsForEvent.php?id=$key" );

answered Jul 04 '14 at 03:34

I'm surprised an 8k user would post an answer to this question instead of finding its duplicate and voting to close... – jeremy Jul 04 '14 at 03:36
1

it's not a duplicate of that question. – sevenseacat Jul 04 '14 at 03:36
It was quicker to type the answer. – Jul 04 '14 at 03:37

score 1 · Answer 2 · answered Jul 04 '14 at 03:35

You have 2 alternatives

1. Change `'` to `"` so that it becomes
header( "Location: http://xx.x.80.94/ants/connie/allExhibitsForEvent.php?id=$key" );

2. Use something like this
header( 'Location: http://xx.x.80.94/ants/connie/allExhibitsForEvent.php?id='.$key );

score 0 · Accepted Answer · edited Jul 04 '14 at 03:36

0

Your using the $key inside of a single quoted string.. Try to use the double quote and it will works well.

header( "Location: http://xx.x.80.94/ants/connie/allExhibitsForEvent.php?id=$key" );

edited Jul 04 '14 at 03:36

NullPoiиteя

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answered Jul 04 '14 at 03:36

Imat

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Vote up the answer? haha lol – Imat Jul 04 '14 at 03:45

Variable not substituting value. What am I doing wrong?

3 Answers3