PHPUnit - Stub private method in mock

Asked Jul 04 '14 at 07:01

Active Jul 04 '14 at 07:16

Viewed 3,188 times

I am writing PHP Unit test and I have class with public method testMeMethod (which I want to test) and private method privateMethod (which is called by public method). I am mocking my class like this:

$constructorArgs = array(
   'foo',
   'void'
);

$myMock = $this->getMockBuilder('\some\namespace\MockMeClass')
            ->setConstructorArgs($constructorArgs)
            ->getMock();

But this will make all methods stubs and I need to test my public method. I need stub just private method, so I tried:

$myMock = $this->getMockBuilder('\some\namespace\MockMeClass')
            ->setConstructorArgs($constructorArgs)
            ->setMethods(array('privateMethod'))
            ->getMock();

$myMock->expects($this->any())->method('privateMethod')->will($this->returnValue('Return this'));

But even after that, if I call:

$myMock->testMeMethod();

Actual public method code is processed, but for private method too. Why is not private method overwritten to simply return Return this without running actual code?

edited Jul 04 '14 at 07:16

asked Jul 04 '14 at 07:01

Pavel Štěrba

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One solution is change private method to protected, but I don't like it. – Pavel Štěrba Jul 04 '14 at 08:10
1

see http://stackoverflow.com/questions/5937845/mock-private-method-with-phpunit?rq=1 – gontrollez Jul 04 '14 at 08:40
You could use Reflection and then mark the class as public to access it. – Steven Scott Jul 04 '14 at 16:25

PHPUnit - Stub private method in mock

0 Answers0