php: echo ('x' == 0) prints 1 (true). is this correct?

Question

my friend and me found this while debugging an application

<?php

echo "check: " . ('x' == 0);

?>

This code prints 1 (so, it is true, x equals to 0). Can somebody explain why it is? I think may be I dont understand something in php rules... or may be it is a bug?

Thank you.

possible duplicate of [Why is integer 0 equal to a string in PHP?](http://stackoverflow.com/questions/13970544/why-is-integer-0-equal-to-a-string-in-php) — Oliver Charlesworth, Jul 06 '14 at 08:44

score 4 · Accepted Answer · answered Jul 06 '14 at 08:42

4

The string is converted to a number using "type juggling". This is shown in the documentation, too.

For this particular case, the string doesn't start with a number, so it becomes equal to 0 when cast.

answered Jul 06 '14 at 08:42

php: echo ('x' == 0) prints 1 (true). is this correct?

1 Answers1

Linked

Related