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i try to create a program to encrypt text into code with my own rule. but, i found some problems to split the text and send it to array

i want to see this in Msg array

Msg[0] = "h";
Msg[1] = "e";
Msg[2] = "l";
Msg[3] = "l";
Msg[4] = "o";

and i try to code like this

String text = "hello";
String[] Msg = new String[] {text};

this code works, but the result isn't like i want. can you help me to solve this problem

thanks..

LockToUnlock
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  • How is it not working? What you're showing it's doing at the top appears to be what I would expect it to do. What is the result that you would like? – krillgar Jul 10 '14 at 23:06
  • possible duplicate of [string to string array conversion in java](http://stackoverflow.com/questions/3413586/string-to-string-array-conversion-in-java) – azurefrog Jul 10 '14 at 23:08
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    Do you want to get array of characters? If so you can get `char []` via `yourString.toCharArray()`. Or do you really want to get array of Strings with each character separated? – Pshemo Jul 10 '14 at 23:08

2 Answers2

6

If you want to split the string up into each character then use this code:

String text = "hello";
String[] Msg = text.split("(?!^)");

This uses a regular expression to split the code by every spot that is between two characters (excluding the first blank spot).

Here's how it works:

.split(""); would be fine for splitting the string if you're using java 8 as @Pshemo pointed out. But below that you will end up with an array that starts with "" as the first element.

This regular expression avoids that because it uses a negative lookahead (?!) to make sure to not match the beginning of a line, which is represented by the ^ character.

BitNinja
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    Any explanation of `(!?^)`? BTW [this regex is no longer needed since Java 8](http://stackoverflow.com/questions/22718744/why-does-split-in-java-8-sometimes-removes-empty-strings-if-they-are-at-start-of), you can just use `split("")`. – Pshemo Jul 10 '14 at 23:11
  • please explain why this would be preferable to simply `toCharArray()`? – drew moore Jul 10 '14 at 23:11
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    @drewmoore Different return types, this actually does **exactly** what OP *described* in example (it returns `String[]`, not `char[]`). – Pshemo Jul 10 '14 at 23:12
  • @drewmoore Because the OP requests that the array be of `String`. – BitNinja Jul 10 '14 at 23:13
  • indeed he does. i'm sorry, i misread the question.. – drew moore Jul 10 '14 at 23:13
4

char[] String.toCharArray() is probably what you are looking for.

See: http://docs.oracle.com/javase/7/docs/api/java/lang/String.html#toCharArray()

dan.m was user2321368
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  • The desired output indicates that `Msg` is a `string[]` and not a `char[]`. Why would someone do that, I don't know, but I'm afraid this does not answer the question. – SirDarius Jul 10 '14 at 23:12
  • Sometimes the asker doesn't really know what they want. Hence the "is probably what you are looking for". @BitNinja's answer above is the solution if the OP's question was exactly what he was asking for. – dan.m was user2321368 Jul 10 '14 at 23:24