Can't get very last part of URL

Question

So here's what my URL looks like

http://localhost/search/s.php?search_query=#hashtag

My first response to this was to use $_GET

$search = htmlspecialchars($_GET['search_query'], ENT_QUOTES, 'UTF-8');

So I'd then end up getting nothing, since I had a # at the end. So I then tried

$url = "http://$_SERVER[HTTP_HOST]$_SERVER[REQUEST_URI]";
$path = parse_url($url, PHP_URL_PATH);
$pathFragments = explode('/', $path);
$id = end($pathFragments);

I'd echo $id, and yet once again get s.php instead.

So my question is, how can I properly do this? I've seen some posts. But none seem to solve my issue.

I'm just trying to get #hashtag.

I don't think the hashtag-part is a part of the `REQUEST-URI` — Max, Jul 12 '14 at 19:58
No need for validation. I just want to get `#hashtag` from the URL. I'd also be having regular words so it has to be dual functioning. @Braj — , Jul 12 '14 at 19:59
@max its not the only way I know to get it to the server is to use javascript and ajax — ArtisticPhoenix, Jul 12 '14 at 19:59
possible duplicate of [Pound sign (#) not working in PHP](http://stackoverflow.com/questions/7479638/pound-sign-not-working-in-php) — Giacomo1968, Jul 12 '14 at 19:59
Well, `parse_url()` should return a `fragment` index that gives you it, but probably only if the parsed URL contains a fragment (something after a hashtag). — Max, Jul 12 '14 at 20:00
see this question http://stackoverflow.com/questions/14462218/is-the-url-fragment-identifier-sent-to-the-server and the answer " Fragment identifiers are not sent to the server. The hash fragment is used by the browser to link to elements within the same page. " ergo you must use some other method to send it to the server, for example ajax — ArtisticPhoenix, Jul 12 '14 at 20:14
If you paste the HTML of the form you are using I can update my answer with the proper jQuery selectors. — ArtisticPhoenix, Jul 12 '14 at 20:17

score 0 · Answer 1 · answered Jul 12 '14 at 20:01

You have to send the hashtag to the backend by making an AJAXrequest, preferrably with jQuery. Any URL in the $_SERVER global variable does not preserve the fragment identifier (the part followed by the # - pound sign).

var hash = window.location.hash;

$.ajax({ ... });

ArtisticPhoenix · Answer 2 · 2014-07-12T20:08:46.663

0

with javascript

var url = 'http://localhost/search/s.php?search_query=#hashtag';

$(form).submit(function(e){
var url = field.val();
   if(url != '' ){
        var hashtag = url.split('#')[1];
       $.post(serverPageUrl, { "hashtag" : '#'+hashtag }, function(data){
            window.location.href = url; //redirect to simulate original get request.
       });
  }
   return false;
});

edited Jul 12 '14 at 20:08

answered Jul 12 '14 at 20:02

ArtisticPhoenix

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so, dynamically send it. even better reason to use javascript – ArtisticPhoenix Jul 12 '14 at 20:03
Not really sure how to _dynamically_ send it over. – Jul 12 '14 at 20:06
how do they change it? trigger the ajax then – ArtisticPhoenix Jul 12 '14 at 20:06
I'm using a form with `GET`. So they submit it, then I pass it through. – Jul 12 '14 at 20:07
there updated the answer, you'll probably have to use post though. And here is docs on submit() http://api.jquery.com/submit/, just make sure to return false; like In my example. – ArtisticPhoenix Jul 12 '14 at 20:09

Braj · Answer 3 · 2014-07-12T20:10:12.667

0

Try with Negative Lookahead

(?!=#)#\w+$

Online demo

Use (?!=#)#.*$ if there is any thing other then words after # till the end of line.

Or try using grouping. Get the matched group from index 1.

^[^#]*+(.*)$

Online demo

Sample code:

$re = "/(?!=#)#\\w+$/";
$str = "http://localhost/search/s.php?search_query=#hashtag";

preg_match_all($re, $str, $matches);

Output:

#hashtag

edited Jul 12 '14 at 20:10

answered Jul 12 '14 at 20:03

Braj

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Hash tags are not sent to the server. – ArtisticPhoenix Jul 12 '14 at 20:03
You are looking for regex pattern to get the #hashtag? – Braj Jul 12 '14 at 20:05
No, just to get whatever is at the end of the url.. And also include the `#` – Jul 12 '14 at 20:05
so its not the executed result that is given by regex? – Braj Jul 12 '14 at 20:07

Can't get very last part of URL

3 Answers3