How to pass shell variable into awk

Asked Jul 15 '14 at 15:55

Active Jul 15 '14 at 15:55

Viewed 32 times

I have a bunch of remote branches on my git server that all start w/ the same prefix

  origin/feature/100-use-email-to-get-all-sockets
  origin/feature/101-remove-buttons-on-response
  origin/feature/102-delete-removes-from-store
  origin/feature/103-erik-fix-moderator-logged-multiple-times-when-logged-in-as-admin-and-client
  origin/feature/31-client-accordian-list-on-admin-side
  origin/feature/33-video-skin-ios
  ...

quite frequently I need to clean up the server and purge all the old-outdated branches

I'm trying to write a script, but I want the ability to pass in a variable that I want to target instead of hard coding like "feature", "bug", etc...

How can I incorporate this variable into this command? all the examples I've found seem to fail.

TGT=feature
git branch -r | awk -F/ '/\/feature/{print $3}'

What I'm looking for is something like

TGT=feature
git branch -r | awk -F/ '/\/$TGT/{print $3}'

asked Jul 15 '14 at 15:55

veilig

5,085
10
48
86

1

Use `-v` to give shell variables to awk: `awk -v myvar=$your_var '{...}'` etc – fedorqui Jul 15 '14 at 15:58
@fedorqui does variable expansion works within `//`? – Avinash Raj Jul 15 '14 at 15:59
I already tried playing w/ the -v flag but that didn't seem to work. I think my syntax in the quoted portion was incorrect – veilig Jul 15 '14 at 15:59
1

@AvinashRaj I think not, but you can write `awk -v myvar="$yourvar" '$0 ~ myvar'` If you want regex matching – user000001 Jul 15 '14 at 16:00
@AvinashRaj exactly what user000001 said. You can test for example `awk -v v="el" '/v/' file` does not work, while `awk -v v="el" '$0 ~ v' file` does. (sample file contains `hello` and `bye`). – fedorqui Jul 15 '14 at 16:08
@fedorqui haha yep, i know. – Avinash Raj Jul 15 '14 at 16:11

How to pass shell variable into awk

0 Answers0