Django dynamic template variable inside if clause

Question

Here's what I'm trying to achieve in "pseudo code":

{% for page in pages %}
    {% if 'can_access_page_{{page.name}}' in perms  %}
        <li>
            <a href="{{page.url}}" id="page_link_{{page.id}}" target="_blank">{{ page.name }}</a>
        </li>
    {% endif %}
{% endfor %}

How to do this? Permission names I can customize — but still can't figure out this one.

score 1 · Answer 1 · answered Jul 22 '14 at 11:55

1

You'll need a custom filter. Something like:

@register.filter
def check_page_perms(page, perms):
    return 'can_access_page_%s' % page.name in perms

and use it:

{% if page|check_page_perms:perms %}

answered Jul 22 '14 at 11:55

Daniel Roseman

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Thanks, I ended up using add template filter. – Capuchin Jul 22 '14 at 13:57

score 1 · Accepted Answer · edited May 23 '17 at 12:27

1

Simplest way is to slightly abuse Django's existing add template filter (intended for numbers but works for strings), as in this answer:

https://stackoverflow.com/a/4524851/202168

edited May 23 '17 at 12:27

Community

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1

answered Jul 22 '14 at 12:57

Anentropic

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Thanks, I made it this way. – Capuchin Jul 22 '14 at 13:56

Django dynamic template variable inside if clause

2 Answers2