Templated arguments

Question

What is proper syntax for a function that takes a template parameter as an argument i.e.

 void myFunction (const Foo::Bar<T>& x)

Is it

 template<typename T>
 void myFunction (const typename Foo::Bar<T>& x)

Also, should I use

template<typename T>

Or

template<class T>

Thanks.

See http://stackoverflow.com/questions/610245/where-and-why-do-i-have-to-put-the-template-and-typename-keywords?rq=1 and http://stackoverflow.com/questions/213121/use-class-or-typename-for-template-parameters?rq=1 (note both of these are in the related links on the right) — chris, Jul 23 '14 at 18:18

score 0 · Accepted Answer · edited May 23 '17 at 12:27

0

You got it.

template<typename T>
void myFunction (const typename Foo::Bar<T>& x)

Is correct. It doesn't matter whether you use class or typename. typename is preferred, class is in there for historical reasons. They are completely identical, though. Check out this question for some explanation.

edited May 23 '17 at 12:27

Community

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answered Jul 23 '14 at 18:21

jaredready

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Templated arguments

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