How to use ApfloatMath.round()?

Question

In this snippet I expected "2" as the result?

Apfloat f = new Apfloat("1.5", 50);
f = ApfloatMath.round(f, 15, RoundingMode.HALF_UP);
System.out.println(f.toString());

Or should ApfloatMath.round() be used differently?

You expect 2 but what you get in `System.out.println(f.toString());` — Jens, Jul 24 '14 at 08:03

score 1 · Accepted Answer · answered Jul 24 '14 at 08:27

1

I have never heard of apfloat but one google query showed me:

round(Apfloat x, long precision, RoundingMode roundingMode)

So apparently you are rounding with a precision of 15, why do you expect 1.5 to magically become 2?

In other words: set precision to 0 or 1 (depends on the implementation)

answered Jul 24 '14 at 08:27

nablex

f = ApfloatMath.round(f, 1, RoundingMode.HALF_UP); thanks this works :-) – axelclk Jul 24 '14 at 08:39

1 Answers1