groovy.json.JsonSlurper parse JSON

Question

I'm trying to parse a JSON-File in my gradle task.

CODE:

def jsonFile = "../files/json/myJSON.json"
def list = new JsonSlurper().parseText(jsonFile)

JSON - FILE

{
   "prepare": {
       "installed": [],
       "uninstalled": []
   },
   "config": {
       "files": []
   }
}

But the code gives me the following exception:

Lexing failed on line: 1, column: 1, while reading '.', no possible valid JSON value or punctuation could be recognized.

And I don't understand why, I also validated my JSON-File on http://jsonlint.com/ and it says that it is a valid JSON!

Peter Niederwieser · Accepted Answer · 2014-07-25T11:30:58.840

1

Above code is trying to parse the string ../files/json/myJSON.json as JSON. Instead use:

def jsonFile = new File("../files/json/myJSON.json")
def map = new JsonSlurper().parse(jsonFile)

edited Jul 25 '14 at 11:30

answered Jul 25 '14 at 11:04

the path is longer, but I accidentally wrote it incorrect. I updated now. – Paul Jul 25 '14 at 11:11
Same problem regardless of the path. – Peter Niederwieser Jul 25 '14 at 11:12
It works now. But to your code I added .getText(). Danke schön! – Paul Jul 25 '14 at 11:20
1

for me didn't work without it. No signature of method: groovy.json.JsonSlurper.parseText() is applicable for argument types: (java.io.File) values: – Paul Jul 25 '14 at 11:24
1

My solution targets Groovy 2.2+/Gradle 2.0+. For Gradle 1.x, `.parse(jsonFile.text)` can be used. – Peter Niederwieser Jul 25 '14 at 11:42
This may help https://stackoverflow.com/questions/41305311/jsonslurper-execution-failure – CodeRunner May 27 '21 at 15:23

1 Answers1