NSNumber to NSInteger gives wrong value?

Question

I have an NSNumber funds. When I do:

NSLog(@"%@ %i", funds, [funds integerValue]);

I get:

4869222353 574255057

Completely different numbers. The first one is correct, so there must be something wrong with converting it to integer. What am i doing wrong?

Thanks.

score 4 · Accepted Answer · edited May 23 '17 at 10:29

4

Sample Code :

NSNumber *myNum = [NSNumber numberWithLongLong:4869222353];
NSLog(@"%@ %lld",myNum,[myNum longLongValue]);

edited May 23 '17 at 10:29

Community

answered Jul 29 '14 at 08:58

Bhavin

1

Thanks. I choose your answer because you provided a solution and a reason behind it. – 0xSina Jul 29 '14 at 18:14

score 3 · Answer 2 · answered Jul 29 '14 at 08:55

3

You have overflow. Integer is 32 bit long and is signed so max value is 2147483647. Printing NSNumber does it in proper way (probably using long).

answered Jul 29 '14 at 08:55

blazejmar

Yes this is correct, on 32bit iOS devices the max integer value is: `2,147,483,647` thus `4,869,222,353` is exceeding it. – rckoenes Jul 29 '14 at 08:59

2 Answers2