How to create plots dynamically in grid.arrange in R?

Question

I have a function get.single.plot, which takes one character argument and returns a ggplot2 plot object. I would like to build a grid.arrange object with n plots on it, where the n is the size of vector of (mentioned) character arguments.

E.g., I woould like something like this to work:

character.argument.vector <- c("12", "1", "2")
grid.arrange(unlist(lapply(character.argument.vector, function(n) get.single.plot(n))),
         ncol = 1)

Such thing does not work - I receive the following information:

Error in arrangeGrob(..., as.table = as.table, clip = clip, main = main,  : 
input must be grobs!

How should I do it?

Thank you, @baptiste ! It is not the first time you helped me, I really appreciate your contribution to the community! — Marta Karas, Jul 30 '14 at 07:41
@Marciszka, that's probably because he is the author of `gridExtra` package... — David Arenburg, Jul 30 '14 at 08:05
does this only work work ggplots? I am using the standard plot() and using the same syntax that baptiste gives, and I get the same error as OP — brucezepplin, Jun 12 '15 at 17:12

baptiste · Answer 1 · 2016-03-04T10:54:11.737

2

With gridExtra v>=2.0 you can simply pass a list of grobs (or plots) to grid.arrange,

grid.arrange(grobs = lapply(...), ncol=1)

edited Mar 04 '16 at 10:54

answered Dec 31 '15 at 22:06

baptiste

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How to create plots dynamically in grid.arrange in R?

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