Creating a URI from URL

Question

I'm trying to create a URI from a URL for my Android application.

I've found the answer here How to create a Uri from a URL? but sadly, I am getting an exception

java.net.MalformedURLException

My code is

URL connection_url = new URL("http://www.google.com"); // exception on this line
URI uri = url.toURI();

I am importing the following

import java.net.URI;
import java.net.URL;

I'm not sure what I've done wrong

Edit

Updated from www.google.com to http://www.google.com - same error

Did you really write `hpttp:`? This indeed gives a `MalformedURLException` — Henry, Aug 02 '14 at 15:45
Again, post the full stack trace with the full error message. — Sotirios Delimanolis, Aug 02 '14 at 15:48
http://docs.oracle.com/javase/tutorial/essential/exceptions/handling.html — Reinstate Monica -- notmaynard, Aug 02 '14 at 15:54

Henry · Accepted Answer · 2014-08-02T15:41:02.660

1

"www.google.com" not a valid URL as it misses the protocol part. Try something like:

URL connection_url = new URL("http://www.google.com");

For example this works without problems:

public static void main(String[] args) throws MalformedURLException, URISyntaxException {
    URL connection_url = new URL("http://www.google.com");
    URI uri = connection_url.toURI();
    System.out.println(uri);
}

edited Aug 02 '14 at 15:41

answered Aug 02 '14 at 15:33

Henry

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Copying and pasting the code still fails in the same manner I describe above, until I do the throws MalformedURLExpcetion, URISyntaxException – MyDaftQuestions Aug 02 '14 at 15:46

score 0 · Answer 2 · answered Aug 02 '14 at 15:34

0

Check this

Uri uri =  Uri.parse("http://www.google.com");

answered Aug 02 '14 at 15:34

Bishan

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Creating a URI from URL

2 Answers2