Illegal character in query URI Syntax

Question

Illegal character in query at index 127: http://192.168.1.7:8080/service-0.0.1-SNAPSHOT/report/genReport/generateReport?reportname=REPORT&doctype=PDF&param={"StartDate":"20140604","EndDate":"20140630","Range":"10"}

can any one help me to get out of this error

What code give you this error? – Ruchira Gayan Ranaweera Aug 07 '14 at 10:39 — Ruchira Gayan Ranaweera, Aug 07 '14 at 10:39
Which is the character at index 127? – Aug 07 '14 at 10:40 — , Aug 07 '14 at 10:40

score 0 · Answer 1 · 2014-08-07T10:48:32.367

0

You should urlencode the JSON

{"StartDate":"20140604","EndDate":"20140630","Range":"10"}

to

%7B%22StartDate%22%3A%2220140604%22%2C%22EndDate%22%3A%2220140630%22%2C%22Range%22%3A%2210%22%7D

The URL will then be

http://192.168.1.7:8080/service-0.0.1-SNAPSHOT/report/genReport/generateReport?reportname=REPORT&doctype=PDF&param=%7B%22StartDate%22%3A%2220140604%22%2C%22EndDate%22%3A%2220140630%22%2C%22Range%22%3A%2210%22%7D

edited Aug 07 '14 at 10:48

answered Aug 07 '14 at 10:42

i can't hard code the json string, it's a json string – Shiva Aug 07 '14 at 10:45
You don't have to hard code anythin. Just have the code that generates this URL encode the JSON into a save format. That's what URL encoding ist for. – Aug 07 '14 at 10:46
Look [here](http://stackoverflow.com/questions/10786042/java-url-encoding) how to do url encoding. – Jens Aug 07 '14 at 11:00

score -2 · Accepted Answer · answered Aug 07 '14 at 10:40

-2

You are trying to send a JSON object via your Get Request.

You should try POST method.

For HTTP Client & Post Method, Check this link

answered Aug 07 '14 at 10:40

gprathour

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This is not an answer, This should be a comment. – Ruchira Gayan Ranaweera Aug 07 '14 at 10:41
this will not be displayed in url, i'll execute this url via httpclient. – Shiva Aug 07 '14 at 10:41
How your answer going to solve the OP's isse? – Ruchira Gayan Ranaweera Aug 07 '14 at 10:45
@Shiva Check the link to see how to send POST request using HTTP Client – gprathour Aug 07 '14 at 10:46
actually i was using httppost to execute the url,after i added namevaluepair, am getting 404,i printed httppost it printed http://192.168.1.7:8080/service-0.0.1-SNAPSHOT/report/genReport/generateReport HTTP/1.1, where this HTTP/1.1 came, and how to know my request is going correctly to the method. – Shiva Aug 07 '14 at 11:37

Illegal character in query URI Syntax

2 Answers2