In the code below I have covered one of two branches of an if statement. But I also want to test the other branch, i.e. when this.tom != null.
public void setTom(boolean cmsConsent, boolean ebConsent) {
if(this.tom== null){
this.tom= new Tom(cmsConsent,ebConsent);
}
}
How to write assert statement so that all branches are covered?
It seems that your field "tom" is a simple private field? If it doesn't get injected, you can't mock it to be or not to be null.
I guess you also have a Getter for that tom object? If you would change your code from:
if(this.tom== null){
to
if(this.getTom() == null){
than you could mock the Getter away using Mockito's SPY functionality. (If you are willing to do so I can explain further)
PS: PowerMock(ito) is always a possibility to enhance your code by byte manipulation, but it should only be used when necessary imo.
Are you calling setTom directly from your test? If so, you don't assert that all branches are covered, you just test all branches via your knowledge of the code. Call setTom twice, once with tom==null and once with tom != null. Branches covered.
