JS split OR Logical Operator

Question

User inputs a web address that I want to get only the tail from, as I do know what site he inputs.

So first I want to remove the "main" URL and get what ever is at the end, so my action is:

Original link: http://example.com/something

var n=e.split("http://example.com/");e=n[1];

And I will get "something"

The problem is that site can also be secured, thus having https not http. Therefore the split wont work.

How do I define a split function, that would work like this:

split("http://example.com/ || https://example.com/")

I do not want to split by looking at "//" or anything of that sort, I want an exact address.

I need to remove from the variable what I wrote: "http://example.com/ || https://example.com" — Yan, Aug 08 '14 at 11:52
I can't understend you (( Could you say what you have on input and what do you want to have on output? — user3917789, Aug 08 '14 at 11:54
`split(/https?:\/\/example\.com\//)` - is this what you have in mind? It's not 100% clear what your goal is. — mingos, Aug 08 '14 at 11:54

score 1 · Answer 1 · edited May 23 '17 at 11:57

1

If you wish to know the host you can do so by using this code instead in JavaScript:

window.location.host

Source Get The Current Domain Name With Javascript (Not the path, etc.)

You can also use window.location.path to get the URL that was requested, combining those you get:

window.location.host + window.location.pathname

For me, this outputs stackoverflow.com/posts/25203020/edit while writing this reply.

edited May 23 '17 at 11:57

Community

1
1

answered Aug 08 '14 at 11:58

Joeppie

438
3
16

It's not a current URL but the one the user inputs in a field. – Yan Aug 08 '14 at 12:02
You should be **very** careful accepting input from the user: Wikipedia has this example URI: foo://username:password@example.com:8042/over/there/index.dtb?type=animal&name=narwhal#nose While a valid 'url' that you can click on, it is very complex and not a case you can easily anticipate. – Joeppie Aug 08 '14 at 12:42
But I do know the start of a URL, it can either be that or that. – Yan Aug 08 '14 at 15:32

score 1 · Accepted Answer · answered Aug 08 '14 at 12:22

1

If you like it clear and want to avoid regular expressions, try this:

var n=e.split("http://example.com/",2).pop().split("https://example.com/",2).pop();

answered Aug 08 '14 at 12:22

chm-software.com

351
2
10

It does work, however, I can't get the whole string at the end with e=n[1]; as I could before. – Yan Aug 08 '14 at 15:38
1

You don't need `n[1]`, the result of the combination of `split()` and `pop()` is a string stored in `n`. If you want `e` to become this string, just add `e = n`. – chm-software.com Aug 11 '14 at 09:36

score 0 · Answer 3 · answered Aug 08 '14 at 13:57

0

var s = "http://example.com/something";
function split (url) {
  var r = /([^:]+):\/\/([^\/]+)\/(.*)/gi;
  var a = r.exec(url)
  return [a[1], a[2], a[3]];
}

answered Aug 08 '14 at 13:57

user3917789

90
4

JS split OR Logical Operator

3 Answers3