In C, I am trying to pass a single-variable function into an optimization routine (optimization_routine
). The optimization routine takes as input a pointer func1ptr
to a function of a single float
variable. However, I need to be able to pass multiple variables into this function. Thus, I am trying to construct a function pointer of one variable where all but the first inputs are "constants" into the function variable (sort of analogous to a partial derivative in calculus). I think I can do this with function pointers, but I can't figure out a syntax that makes sense.
That is, I have a function like this:
float function_all_inputs( float A, int B, float C, char D);
The optimization function requires a pointer like this:
typedef (*func1ptr)(float);
void optimization_function( func1ptr fp );
Thus, I want to construct a function of this form:
// create a function of A only at runtime using inputs B,C,D
func1ptr fp = ( & function_all_inputs(A,B,C,D))(A);
The function pointed to by fp
should have the signature:
float function_one_input(float A);
Inputs B, C, and D are calculated elsewhere in the code, and thus are not known at compile-time; however, they are constant inside optimization_function
.
I think I can do this in pure C using function pointers, however, I can't figure out the correct syntax. None of the examples I found online cover this case. Any advice you can provide would be appreciated.