Java parse a 8601 formatted string to a more readable date parse error

Question

I'm getting dates and trying to parse them into more readable dates but I keep getting a parse error, the formatting looks correct to me but its not working

 DateFormat df = new SimpleDateFormat("yyyy-MM-dd'T'HH:mm'Z'");
 DateFormat df2 = new SimpleDateFormat("yyyy-MM-dd");
    try {
        Date date1 = df.parse(purchase.getRedeem_at());

        String readableDate = df2.format(date1);

        b.append(readableDate);

    } catch (ParseException e) {

        e.printStackTrace();
    }

An example string im trying to parse is

2014-08-12T02:30:00Z

`02:30:00Z`vs `HH:mm'Z'` Should I vote to close as a typo? – Sotirios Delimanolis Aug 12 '14 at 05:02 — Sotirios Delimanolis, Aug 12 '14 at 05:02
well it wasn't a typo it was an incorrent parsing format – Brian Aug 12 '14 at 09:02 — Brian, Aug 12 '14 at 09:02

score 2 · Accepted Answer · answered Aug 12 '14 at 05:06

2

You're missing the seconds part from your first format string.

DateFormat df = new SimpleDateFormat("yyyy-MM-dd'T'HH:mm:ss'Z'");
//                                                       ^

answered Aug 12 '14 at 05:06

Sotirios Delimanolis

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score 2 · Answer 2 · edited Aug 12 '14 at 09:06

2

joda will parse this format right out of the box:

DateTimeFormatter fmt = ISODateTimeFormat.dateTimeNoMillis();
DateTime ourDate = fmt.parseDateTime(jdkDate);

If you have further problems, do leave a comment.

edited Aug 12 '14 at 09:06

Klas Lindbäck

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answered Aug 12 '14 at 05:07

hd1

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naveejr · Answer 3 · 2014-08-12T05:21:53.670

1

You should add "ss"

DateFormat df = new SimpleDateFormat("yyyy-MM-dd'T'HH:mm:ss'Z'");

edited Aug 12 '14 at 05:21

answered Aug 12 '14 at 05:07

naveejr

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Java parse a 8601 formatted string to a more readable date parse error

3 Answers3