How to integrate Spring 4 with Apache Tiles 3?

Question

I am using Spring framework version 4 and I get confused which folder to put the XML files, specially the tile definitions and where to find the resolver bean.

Please add relevant tags when you asking the question, It is very helpful to add peoples attraction. — Ruchira Gayan Ranaweera, Aug 12 '14 at 09:16

score 5 · Answer 1 · edited Oct 21 '14 at 17:32

The tile definition xml is specified when you define the TilesConfigurer bean. If you are using Java-based configuration this would look like:

@Bean
public TilesConfigurer tilesConfigurer(){
    TilesConfigurer tilesConfigurer = new TilesConfigurer();
    tilesConfigurer.setDefinitions(new String[] {"/WEB-INF/**/tiles.xml"});
    tilesConfigurer.setCheckRefresh(true);
    return tilesConfigurer;
}

If you are using xml-based configuration this would look like:

<bean id="tilesConfigurer" class="org.springframework.web.servlet.view.tiles3.TilesConfigurer">
    <property name="definitions">
        <list>
            <value>/WEB-INF/views/**/tiles.xml</value>
        </list>
    </property>
</bean>

When you specify /WEB-INF/views/**/tiles.xml, you are telling the TilesConfigurer to look for all tiles definitions recursively under the /Web-INF/views directory.

Shahid Yousuf · Answer 2 · 2018-07-12T16:49:15.043

you need to configure your servlet-context with couple of beans, make tiles.xml to use layout template and rest of the definitions in views.xml to derive the base definition in tiles.xml:

  <beans:bean id="tilesConfigurer"
    class="org.springframework.web.servlet.view.tiles3.TilesConfigurer">
    <beans:property name="definitions">
        <beans:list>
            <beans:value>/WEB-INF/tiles.xml</beans:value>
            <beans:value>/WEB-INF/views/**/views.xml</beans:value>
        </beans:list>
    </beans:property>
</beans:bean>
<beans:bean id="tilesViewResolver"
    class="org.springframework.web.servlet.view.UrlBasedViewResolver">
    <beans:property name="viewClass">
        <beans:value>
            org.springframework.web.servlet.view.tiles3.TilesView
        </beans:value>
    </beans:property>
    <beans:property name="order" value="0"/>
</beans:bean>

You can also use the TilesViewResolver instead of the UrlBasedViewResolver (``````). You don't need to configure the viewClass then. — OlgaMaciaszek, Jan 04 '16 at 13:29

score 0 · Accepted Answer · answered Sep 21 '14 at 19:07

0

The docs should explain all this for you.

answered Sep 21 '14 at 19:07

mck

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How to integrate Spring 4 with Apache Tiles 3?

3 Answers3