I need a simple command line program to transform XML using an XSL Stylesheet

Question

I am on OSX Snow Leopard (10.6.2) I can install anything I need to. I would preferably like a Python or Java solution. I have searched on Google and found lots of information on writing my own program to do this, but this is a just a quick and dirty experiment so I don't want to invest a lot of time on writing a bunch of code to do this, I am sure someone else has done this already.

This is off-topic now, do not use this question as an example of why your recommendations request is on topic, it is not. I apologize, but my Google-Foo was failing me the day I asked this 4 years ago!

score 24 · Accepted Answer · answered Mar 27 '10 at 05:23

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Have you tried 'xsltproc'? It's probably already installed.

http://xmlsoft.org/XSLT/xsltproc2.html

answered Mar 27 '10 at 05:23

nbeyer

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you are right OSX Snow Leopard 10.6.2 already has this installed, so it gets the check mark! – Mar 27 '10 at 19:26
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`xsltproc stylesheet file` outputs to stdout. Awesome. – npdoty Oct 14 '11 at 03:11
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Unfortunately `xsltproc` does not work with XSLT 2.0 as far as I can tell. – stiemannkj1 May 21 '14 at 18:53

score 17 · Answer 2 · answered Mar 26 '10 at 21:02

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I'd recommend Saxon, which can be run from the command line like so:

java -jar /path/to/saxon.jar xmlfile xslfile

answered Mar 26 '10 at 21:02

Will McCutchen

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Add the -o argument to create an outputfile. `java -jar -o:` – Paul Wasilewski Feb 13 '14 at 09:10
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Awesome, `saxon.jar` works with XSLT 2.0! – stiemannkj1 May 21 '14 at 18:54

score 5 · Answer 3 · answered Mar 26 '10 at 21:01

Have you seen XMLStarlet (an XML command line toolset) ? It does lots of XML-related querying transformation, and in particular:

xml tr --help
XMLStarlet Toolkit: Transform XML document(s) using XSLT
Usage: xml tr [<options>] <xsl-file> {-p|-s <name>=<value>} [ <xml-file-or-uri> ... ]
where
   <xsl-file>      - main XSLT stylesheet for transformation
   <xml-file>      - input XML document file name (stdin is used if missing)
   <name>=<value>  - name and value of the parameter passed to XSLT processor
   -p              - parameter is XPATH expression ("'string'" to quote string)
   -s              - parameter is a string literal

Further documentation here.

score 4 · Answer 4 · answered Mar 26 '10 at 20:59

If I assume correctly that you want to supply a stylesheet and an XML document then Xalan-J has a command line feature you can use to do this:

http://xml.apache.org/xalan-j/commandline.html

which can be invoked with:

java org.apache.xalan.xslt.Process -IN foo.xml -XSL foo.xsl -OUT foo.out

score 3 · Answer 5 · answered Mar 26 '10 at 20:57

3

http://xml.apache.org/xalan-j/

answered Mar 26 '10 at 20:57

S.Lott

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score 3 · Answer 6 · answered Mar 26 '10 at 20:58

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Use lxml. It is very easy to use and very fast. It can work with XPath and includes a XSLT transformer.

answered Mar 26 '10 at 20:58

nosklo

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score 0 · Answer 7 · edited May 23 '17 at 11:54

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see this question for another solution with com.sun.org.apache.xalan.internal.xsltc.cmdline.Transform. But I noticed some weirdness with namespaces compared to xalan processing. Be aware behavior might be non standard.

Also you know, internal java classes are not good to rely on.

edited May 23 '17 at 11:54

Community

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answered Dec 17 '12 at 15:51

akostadinov

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score 0 · Answer 8 · answered Mar 29 '10 at 22:46

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I have used Saxon 6.5 for years for command line transformations. (Java, XSLT 1)

An excellent fallback if a native solution is not available.

answered Mar 29 '10 at 22:46

Thorbjørn Ravn Andersen

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I need a simple command line program to transform XML using an XSL Stylesheet

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