Simple functionnal way for grouping successive elements?

Asked Aug 12 '14 at 18:47

Active Aug 12 '14 at 18:47

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Let's take the string "AAAABCCCBBBBBBAAACC" : I would like to build a kind of Iterable such as this Vector [('A', 4), ('B',1), ('C', 3), ('B', 6), ('A',3), ('C', 2)] (which list letters occurences in order). What is the simplest functionnal approch for doing that in Scala ?

All I've found is to use a for clause (or a foreach call) and to rely upon some vars : nothing better. Is there a single method that I can call on my collection (or a method chain) ?

Indeed, after having written several codes, it seems that doing this is a recurring pattern to me.

asked Aug 12 '14 at 18:47

loloof64

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Are you trying to reimplement or do you just want a working function? Because Scala has a groupBy method – dsemi Aug 12 '14 at 18:50
GroupBy seems good to me : how can I use this function with the string I gave above ? (It seems it take a single argument) – loloof64 Aug 12 '14 at 18:53
`groupBy` will group also non consecutive letters, eg in your case `A` will have 7 as value and not 4. – Ende Neu Aug 12 '14 at 18:54
Yes it fit to my needs : that's a duplicate. Apologizing – loloof64 Aug 12 '14 at 18:56

Simple functionnal way for grouping successive elements?

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