What is android replacement for $.ajax with array

Question

I have existing jquery code to submit array 'array' as json var in a login process

var array1 = {
"command" : "login",
"username": $("#txt_username").val(),
"password": $("#txt_password").val(),
"remember":  $('#chk_remember').is(':checked')
};

$.ajax({
                url: 'functions.php',
                data : {'array': array1},
                dataType: 'json',
                type: 'POST',
                success: function(data) {
                    if  (data.success == 1 ){

                   $('#result').html("You have been logged in.</br>You will be     redirected to another page");
}
});

and at PHP

if (isset($_POST["array"])) {
$array = $_POST['array'];
switch ($array["command"]) {
    case "login" :
        if (DoLogin($array["username"], $array["password"]) == true) {
            $success = 1;
}
        else {
            $success = 0;
        }
        $arr = array("success" => $success, "redirect" => 1);

        echo json_encode($arr);
break;
}

how to deal with this login process from android?

It is a javascript but i need to repeate the process in Android code — Eslam Sameh Ahmed, Aug 12 '14 at 22:29
If you are making a connection in a Java application, you'll need to research how to do that. I'd start with a search for "cURL post Java Android", that should get you lots of good research links. — halfer, Aug 12 '14 at 22:31
Oh, you mean you're writing a stand-alone Android **application** and not a web application. Well it's a completely different affair. — Pointy, Aug 12 '14 at 22:32
I already know how to send list of string variables over Json but what i need is to encode and decode an array object over JSON — Eslam Sameh Ahmed, Aug 13 '14 at 08:47

score 2 · Answer 1 · answered Aug 12 '14 at 22:50

public class Utils {

    public static String POST(String url, Login login){
        InputStream inputStream = null;
        String result = "";
        try {

            // 1. create HttpClient
            HttpClient httpclient = new DefaultHttpClient();

            // 2. make POST request to the given URL
            HttpPost httpPost = new HttpPost(url);

            String json = "";

            // 3. build jsonObject
            JSONObject jsonObject = new JSONObject();
            jsonObject.accumulate("command", login.command);
            jsonObject.accumulate("username", login.username);
            jsonObject.accumulate("password", login.password);
            jsonObject.accumulate("remember", login.remember);

            // 4. convert JSONObject to JSON to String
            json = jsonObject.toString();

            // ** Alternative way to convert Login object to JSON string usin Jackson Lib
            // ObjectMapper mapper = new ObjectMapper();
            // json = mapper.writeValueAsString(login);

            // 5. set json to StringEntity
            StringEntity se = new StringEntity(json);

            // 6. set httpPost Entity
            httpPost.setEntity(se);

            // 7. Set some headers to inform server about the type of the content
            httpPost.setHeader("Accept", "application/json");
            httpPost.setHeader("Content-type", "application/json");

            // 8. Execute POST request to the given URL
            HttpResponse httpResponse = httpclient.execute(httpPost);

            // 9. receive response as inputStream
            inputStream = httpResponse.getEntity().getContent();

            // 10. convert inputstream to string
            if(inputStream != null)
            result = convertInputStreamToString(inputStream);
            else
            result = "Did not work!";

            } catch (Exception e) {
            Log.d("InputStream", e.getLocalizedMessage());
        }

        // 11. return result
        return result;
    }
}

// Model login obj
public class Login {
    public String password;
    public String username;
    public String command;
    public boolean remember;
}

Into Activity

Login login = new Login();

// get reference to the views
login.username = (EditText) findViewById(R.id.user);
login.password = (EditText) findViewById(R.id.pass);
login.command = (EditText) findViewById(R.id.comm);
login.remember = ((CheckBox) findViewById(R.id.rem)).isChecked();

Utils.POST(stringUrl, login) // use AsynckTask for this http://stackoverflow.com/questions/8829135/android-http-request-asynctask

Will not work as the PHP code is looking first for an array called 'array' in the post then it is looking inside th array for 'command' item and user/password items are inside the array — Eslam Sameh Ahmed, Aug 13 '14 at 08:50

score 1 · Answer 2 · answered Aug 13 '14 at 03:49

1

I'd recommend looking into using Volley to handle your web requests. This is a handy guide to get started: http://www.androidhive.info/2014/05/android-working-with-volley-library-1/

answered Aug 13 '14 at 03:49

Andrew Breen

685
3
11

What is android replacement for $.ajax with array

2 Answers2