why does following code give different output in C , C++?

Question

The following code gives output as 1, 4, 4 in C whereas 1, 1, 4 in C++

#include<stdio.h> 
int main() 
{  
    char ch = 'A'; //initialise 
    //printing output
    printf("%d, %d, %d", sizeof(ch), sizeof('A'), sizeof(3.14f));    
    return 0; 
}

but its not at stackoverflow i searched it here at stackoverflow n didn't found any similar one. well i got the answer thts important for me. thank you — Ashutosh Soni, Aug 14 '14 at 11:37
`i searched it here at stackoverflow n didn't found any similar one`. dont understand. is stackoverflow answer different then that one? — Jayesh Bhoi, Aug 14 '14 at 11:39
no but that is at geeksforgeeks.org n people are marking this one as duplicate , i thought you are also amongst them that's why — Ashutosh Soni, Aug 15 '14 at 15:53

score 9 · Accepted Answer · answered Aug 14 '14 at 11:27

9

Because a character literal is of type int in C but of type char in C++.

answered Aug 14 '14 at 11:27

wilx

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why does following code give different output in C , C++?

1 Answers1