Bar
is a non dependent name (i.e. its type does not depend on T
), so the compiler is required to verify the correctness of the code during the first phase of name-lookup (see the note below).
Since Bar
has no nonexistent_method()
method, the compiler is required to issue a diagnosis.
If you change your template to:
template<typename T>
void foo(T t, T bar) {
t.compiler_does_not_care();
bar.nonexistent_method();
}
No non-dependent names are involved, so no error is emitted since the template is never instantiated (phase 2 of the lookup)
Notes:
- Comprehensible description of two-phase name lookup from LLVM :
1) Template definition time: when the template is initially parsed, long before it is instantiated, the compiler parses the template and
looks up any "non-dependent" names. A name is "non-dependent" if the
results of name lookup do not depend on any template parameters, and
therefore will be the same from one template instantiation to another.
2) Template instantiation time: when the template is instantiated, the compiler looks up any "dependent" names, now that it has the full
set of template arguments to perform lookup. The results of this
lookup can (and often do!) vary from one template instantiation to
another.
- As for the why non-dependent name lookup can't be deferred to the second stage, see this other SO post; it seems that it is mostly for historical reasons.