lexical scope, what about side by side?

Question

Articles I've read on scope in javascript address what happens when you have nested variables/objects/functions defined in its parent scope. However, what happens if you have something like this:

function x(){

function y(){var u = 3;}
function z(){//is u available here?}

}

Omitting newlines isn't going to affect the scope... And no, `u` is not accessible there (which you could have found out yourself in 4 seconds). — Marty, Aug 21 '14 at 03:10
This question appears to be off-topic because it is about a question which could be easily answered with a one-second test. — , Aug 21 '14 at 03:26
@torazaburo—if the OP doesn't know that, then they require more than a yes or no answer. — RobG, Aug 21 '14 at 03:37
@slynthin If you see "'u' is undefined" in the console log, then that means that the Fiddle is working. — JLRishe, Aug 21 '14 at 04:10

score -1 · Answer 1 · answered Aug 21 '14 at 03:22

-1

var u in function y is not available in function z. However it will be accessible in you omit the var.

u = 3; // instead of var u = 3;

omitting the "var" will make the variable global.

answered Aug 21 '14 at 03:22

eman.lodovice

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It should be avoided of omitting the "var" – dencey Aug 21 '14 at 03:24
I agree. I just mentioned it for the sake of the discussion about scope. :) – eman.lodovice Aug 21 '14 at 03:27
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*u* is only global after the code assigning to it executes, before then it's not defined. Maybe mention strict mode restrictions? – RobG Aug 21 '14 at 03:34

lexical scope, what about side by side?

1 Answers1