Logger module wants to know the path of the module that initialized it

Question

I have a custom logger defined in

/utils/my_logger.py

class MyLogger():
    def __init__(self, name, path_of_module):
        self.logger_name = name
        self.path = path_of_module

    def get_logger(self):
        ...
        #setLevel, formatter, handler, etc.
        return logger

say, in another file somewhere I import and instantiate MyLogger..

/some/path/to/foo.py

handler = MyLogger("testing", os.path.realpath(__file__))
log = handler.get_logger()

Is there any way to do this so that I don't have to explicitly write os.path.realpath(__file__) as an argument every time I instantiate the logger?

score 4 · Accepted Answer · edited May 23 '17 at 10:33

4

You can use the inspect module to look for the caller on the stack. From there, you can get the caller's module and __file__. Look at Get name of calling function's module in Python - its getting module name but the same goes for the file name.

edited May 23 '17 at 10:33

Community

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answered Aug 27 '14 at 16:08

tdelaney

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score 1 · Answer 2 · answered Aug 27 '14 at 16:13

1

How about this:

import inspect
os.path.abspath(inspect.stack()[-1][1])

answered Aug 27 '14 at 16:13

Vor

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e-nouri · Answer 3 · 2014-08-27T16:15:53.170

0

[Edit]: changed to os.getcwd() Do it in the init method,

def __init__(self, name):
        self.logger_name = name
        self.path = os.getcwd()

Isn't that better ?!

edited Aug 27 '14 at 16:15

answered Aug 27 '14 at 16:08

e-nouri

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That gets the module the class is defined in, not the module that instantiates the class. – tdelaney Aug 27 '14 at 16:08

Logger module wants to know the path of the module that initialized it

3 Answers3