rfftw2d_create_plan implementation in c++

Question

I am trying to perform FFT using the FFTW lib available for c++. Since there are many options for FFTW available i am trying to implement fft using the rfftwnd method(since my data is real).

 #include<rfftw.h>
{
fftw_real a[width][2*(height/2+1)],b[width][2*(height/2+1)],c[width][height];
fftw_complex *A,*B,C[width][height/2+1];

rfftwnd_plan rp,rpin;
fftw_real scale = 1.0/(width*height);

const int H = height;
const int W= width;
rp = rfftw2d_create_plan(W,H,FFTW_REAL_TO_COMPLEX,FFTW_ESTIMATE);
rpin = rfftw2d_create_plan(width, height, FFTW_COMPLEX_TO_REAL,FFTW_ESTIMATE);

A = (fftw_complex*) &a[0][0];
B = (fftw_complex*) &b[0][0];
for(int i=0;i<width;i++)
{
    for (int j=0;j<height;j++)
    {
        a[i][j] = la(i,j);
    }
}
 }

So i am basically trying to implement the fft on an image for this i need to create the plans as suggested in the FFTW documentation. But when i do this i get an errror saying

 error: undefined reference to `rfftw2d_create_plan'

could someone please help as to why this is happening? Am i missing something here?

If this is new development, you might want to consider starting with FFTW 3 since FFTW 2 has been marked as obsolete (see [FFTW's download page](http://www.fftw.org/download.html)) — SleuthEye, Aug 29 '14 at 13:05

score 0 · Accepted Answer · edited May 23 '17 at 12:12

This is a linker error which tells you that the linker cannot find the indicated function, with the most likely reason being that the linker doesn't know about the librfftw.a library which contains the definition (see this question & answers for more details, and more specifically this answer).

According to this section of FFTW documentation:

Programs using RFFTWND should be linked with -lrfftw -lfftw -lm on Unix systems, or with the FFTW, RFFTW, and standard math libraries in general.

So, you should be adding those required flags for compilation.

rfftw2d_create_plan implementation in c++

1 Answers1