I have an array of objects that can be of any length and any depth. I need to be able to find an object by its id and then modify that object within the array. Is there an efficient way to do this with either lodash or pure js?
I thought I could create an array of indexes that led to the object but constructing the expression to access the object with these indexes seems overly complex / unnecessary
edit1; thanks for all yours replies I will try and be more specific. i am currently finding the location of the object I am trying to modify like so. parents is an array of ids for each parent the target object has. ancestors might be a better name for this array. costCenters is the array of objects that contains the object I want to modify. this function recurses and returns an array of indexes that lead to the object I want to modify
var findAncestorsIdxs = function(parents, costCenters, startingIdx, parentsIdxs) {
var idx = startingIdx ? startingIdx : 0;
var pidx = parentsIdxs ? parentsIdxs : [];
_.each(costCenters, function(cc, ccIdx) {
if(cc.id === parents[idx]) {
console.log(pidx);
idx = idx + 1;
pidx.push(ccIdx);
console.log(pidx);
pidx = findAncestorsIdx(parents, costCenters[ccIdx].children, idx, pidx);
}
});
return pidx;
};
Now with this array of indexes how do I target and modify the exact object I want? I have tried this where ancestors is the array of indexes, costCenters is the array with the object to be modified and parent is the new value to be assigned to the target object
var setParentThroughAncestors = function(ancestors, costCenters, parent) {
var ccs = costCenters;
var depth = ancestors.length;
var ancestor = costCenters[ancestors[0]];
for(i = 1; i < depth; i++) {
ancestor = ancestor.children[ancestors[i]];
}
ancestor = parent;
console.log(ccs);
return ccs;
};
this is obviously just returning the unmodified costCenters array so the only other way I can see to target that object is to construct the expression like myObjects[idx1].children[2].grandchildren[3].ggranchildren[4].something = newValue. is that the only way? if so what is the best way to do that?