Python equivalent of Ruby's each_with_index?

Question

In Ruby, if I have an array and I want to use both the indexes and the values in a loop, I use each_with_index.

a=['a','b','c']
a.each_with_index{|v,i| puts("#{i} : #{v}") }

prints

0 : a 
1 : b
2 : c

What is the Pythonic way to do the same thing?

[enumerate](https://docs.python.org/3/library/functions.html#enumerate) — grc, Aug 29 '14 at 13:45

score 11 · Accepted Answer · edited Aug 29 '14 at 14:29

11

Something like:

for i, v in enumerate(a):
   print "{} : {}".format(i, v)

edited Aug 29 '14 at 14:29

AShelly

answered Aug 29 '14 at 13:44

klasske

score 4 · Answer 2 · answered Aug 29 '14 at 13:49

4

That'd be enumerate.

a=['a','b','c']
for i,v in enumerate(a):
    print "%i : %s" % (i, v)

Prints

0 : a
1 : b
2 : c

answered Aug 29 '14 at 13:49

gnrhxni

2 Answers2