C: Symbols in array of char

Question

i need to put many symbols in one array of char.

This is my code, I have problem with the single quote symbol, " ' " :

int main()
{
    int i, j;
    int a;
    char alph[] = {'A','B','C','D','E','F','G','H','I','J','K','L','M','N','O','P','Q','R','S','T','U','V','W','X','Y','Z','0','1','2','3','4','5','6','7','8','9','.',',',':','?','=','-','(',')','"',''','/','%','@','!'};
}

Try this `'\''`. And do not forget to read about escape sequences. — haccks, Aug 29 '14 at 14:02
Related question: http://stackoverflow.com/q/11772291/2455888 — haccks, Aug 29 '14 at 14:09
Thanks! it work's for the symbol! But I want to put a word instead the symbol in the array? It's possible? — user3121134, Aug 29 '14 at 14:11
@user3121134 Do not ask another question here, create a new one. — mantal, Aug 29 '14 at 14:51
@user3121134: Please enter a new question, do not use edit to add a new question. — Peter G., Aug 29 '14 at 14:52

score 3 · Accepted Answer · answered Aug 29 '14 at 14:02

3

You can escape the quote with a backslash, i.e. '\''

answered Aug 29 '14 at 14:02

downhillFromHere

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mantal · Answer 2 · 2014-08-29T14:47:28.303

1

To represent ' as a character, you must escape it. In C you do this by using \ : char c = '\'' You don't need to escape ' when using it inside a string (but inside string you need to escape ").

edited Aug 29 '14 at 14:47

answered Aug 29 '14 at 14:03

mantal

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Characters like " **must** be escape using \ is not correct. "The double-quote " and question-mark ? are representable either by themselves or by the escape sequences \" and \?," C11dr §6.4.4.4 4 `'"'` is OK. – chux - Reinstate Monica Aug 29 '14 at 14:18
You must escape the `"` if it's in a double-quote string. You must escape the `'` if it's in a single-quote string (character). You don't need to escape `'"'` or `"don't"`. – hymie Aug 29 '14 at 14:34
@hymie Tanks, I forgot this case. I edited my answer. – mantal Aug 29 '14 at 14:48

C: Symbols in array of char

2 Answers2