Segue from code doesn't work

Question

I've created a segue from one VC to another VC (Dragging form the VC to the other VC), and called it RegisterUserSegue , its a Push segue and all my view controllers are embedded in a navigation controller. I'm calling the segue like this:

[self performSegueWithIdentifier:@"RegisterUserSegue" sender:self];

and in performSegueWithIdentifier I've set an NSLog that is called every time I call the segue, but the viewController doesn't change.

EDIT: however if i comment out the - (void)performSegueWithIdentifier:(NSString *)identifier sender:(id)sender method, everything works just fine.

This is the method:

- (void)performSegueWithIdentifier:(NSString *)identifier sender:(id)sender {
    NSLog(@"Called");
}

help? thanks!

More information maybe? Are you using storyboard? Did you define the Segue as `RegisterUserSegue` ?? — taylorcressy, Aug 30 '14 at 11:05
@taylorcressy I've wrote that I called the segue `RegisterUserSegue`, and yes I use storyboard. — Eli Braginskiy, Aug 30 '14 at 11:08
So, have you set a breakpoint in `performSegueWithIdentifier` and single stepped through? — Paulw11, Aug 30 '14 at 11:19
use this link http://stackoverflow.com/questions/20715462/receiver-viewcontroller-has-no-segue-with-identifier-addsegue/20715545#20715545 — Anbu.Karthik, Aug 30 '14 at 11:31
Wait, did you implement `performSegueWithIdentifier` in your view controller? — taylorcressy, Aug 30 '14 at 12:33

score 4 · Accepted Answer · answered Aug 30 '14 at 11:31

By implementing prepareForSegueWithIdenitifer you have overridden the default implementation in UIViewController with a method that does nothing (except write to the log).

You could use -

- (void)performSegueWithIdentifier:(NSString *)identifier sender:(id)sender {
    [super performSegueWithIdentifier:identifier sender:sender];
    NSLog(@"Called");
}

But you typically do not override this method. If you want to pass properties through to the destination view controller you would use prepareForSegue:sender:

Segue from code doesn't work

1 Answers1