C# Process.Start Path

Question

I currently have a functioning program that simply launches a separate .exe file by clicking a button. The installer I've created asks where they want to install which by default is in fodler C:\Program Files\PRHA.

The code that launches the programs looks like this

private void ivClick(object sender, RoutedEventArgs e)
{
    Process.Start("C:/Program Files/PRHA/IV/IV.exe");
}

How can I have Process.Start find the path of the running application, so if the user decides to install in another directory, Process.Start will still work.

Are you using a deployment project in Visual Studio? Or a custom made installer? — BCartolo, Sep 02 '14 at 15:44
*What I'm wondering is how to have Process.Start find the path if the user decides to install in another directory.* Remember where the program is installed, and use that path — David Heffernan, Sep 02 '14 at 15:45
Currently an installer program called Install Creator, though if necessary I'll change it. — Dylan Banta, Sep 02 '14 at 15:46
John, both EXEs are always installed alongside each other yes. — Dylan Banta, Sep 02 '14 at 15:47

score 2 · Accepted Answer · answered Sep 02 '14 at 15:56

In the event that you just want to get the path of the running application to launch a secondary application (in the same directory) you should be able to use:

System.Reflection.Assembly.GetExecutingAssembly().Location

Reference:
http://msdn.microsoft.com/en-us/library/aa457089.aspx
http://msdn.microsoft.com/en-us/library/system.reflection.assembly.location(v=vs.110).aspx

score 0 · Answer 2 · edited Sep 23 '16 at 20:30

0

I think if you do it this way then there is no need that both have to be in the same location.

We can try having a custom action on the installer of IV.exe that makes a registry entry of the installed path. And whichever is the application that needs to invoke IV.exe will read the registry and gets the path with that specific key.

edited Sep 23 '16 at 20:30

Peter Mortensen

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answered Sep 02 '14 at 16:07

kishore V M

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C# Process.Start Path

2 Answers2