if a word has an even amount of letters print the word with two letters per line?

Question

import java.util.Scanner;

public class TwoAtATime {

  public static void main(String[] args) {
    Scanner scan= new Scanner(System.in);
    System.out.println("Enter a word with an even amount of letters:");
    String w = scan.nextLine();
    if(w.length() % 2 == 0) {
      for(int i= 0; i<w.length(); i++) {
        System.out.println(w.charAt(i));
      }
    } else {
      System.out.println("You didnt follow directions");
    }
  }
}

This is my code so far and I can't figure out how to make it print two per line instead of one, any help?

Eran · Answer 1 · 2014-09-05T01:14:34.650

3

Here's one way to do it :

if (w.length() % 2 == 0) {
    for(int i = 0; i < w.length(); i+=2) {
        System.out.print(w.charAt(i));
        System.out.println(w.charAt(i+1));
    }
}

Or you could do it with String::substring.

if (w.length() % 2 == 0) {
    for(int i = 0; i < w.length(); i+=2)
        System.out.println(w.substring(i,i+2));
}

edited Sep 05 '14 at 01:14

answered Sep 05 '14 at 00:59

Eran

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There's a couple of problems, 1. adding chars does not concatenate them. 2. w.length() doesn't need to be divided by 2. – Nick Grealy Sep 05 '14 at 01:09
@NickG Thanks for the correction. I guess that's one of the risks of answering too fast. Fixed now. – Eran Sep 05 '14 at 01:15
Nice - I like the substring answer! :) – Nick Grealy Sep 05 '14 at 01:20

score 2 · Answer 2 · edited May 23 '17 at 11:49

2

Slight modification to @Eran's answer, you don't need to divide w.length() by 2. Also, adding the char's does not concatenate them.

String w = "12345678";
if (w.length() % 2 == 0) {
    for(int i= 0; i<w.length(); i+=2)
        System.out.println(""+w.charAt(i)+w.charAt(i+1));
}

Gives:

Reference: In Java, is the result of the addition of two chars an int or a char?

edited May 23 '17 at 11:49

Community

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1

answered Sep 05 '14 at 01:07

Nick Grealy

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Uhha · Answer 3 · 2014-09-08T00:16:35.290

1

Just change the "for" loop to this:

 for(int i= 1; i<w.length(); i+=2){
     System.out.println(w.charAt(i-1) +""+ w.charAt(i));
 }

edited Sep 08 '14 at 00:16

answered Sep 05 '14 at 01:10

Uhha

29
3

1

You might want to try testing this (it's wrong, unless I'm mistaken). For "12345678" I'm getting "12", "23", "34", etc. – Nick Grealy Sep 05 '14 at 01:17
Thank you. Had a typo there. Fixed – Uhha Sep 08 '14 at 00:16

score 0 · Answer 4 · answered Sep 05 '14 at 01:21

0

you can use Google Guava which split your string by fixed length (2 in your case).

for(String subStr : Splitter.fixedLength(2).split(w)){
    System.out.println(subStr);
}

here is the java doc for Splitter

answered Sep 05 '14 at 01:21

Yang Zhang

31
2

if a word has an even amount of letters print the word with two letters per line?

4 Answers4