How to take the current url into a php variable?

Question

I want to take the url generated from a dynamic web in to a php variable Suppose there is one adress in url

www.example.com/new/id=2

I want to take the parts new/id=2 in to a php variable.

same time that variable is able to take new/id=2&title=ARTICLE from

www.example.com/new/id=2&title=ARTICLE

Is there any tricks which can do that job?.

Please be more specific when asking questions and research on google — Khan Shahrukh, Sep 06 '14 at 17:16
As a general comment: Depending on the usage this can be dangerous, because attackers could inject arbitrary code (HTML/JavaScript). E.g. by appending ```?"><"``` or ```/"><"``` (directly after the .php ending). — MrTux, Sep 06 '14 at 17:38
@KhanShahrukh pls do one thing Avoid the comment " Please be more specific when asking questions and research on google " Cause lot are telling the same comment And try somthing diffrent!. — Neenu, Sep 07 '14 at 10:48

score 2 · Accepted Answer · answered Sep 06 '14 at 17:14

2

Try this

$full_url = "http://$_SERVER[HTTP_HOST]$_SERVER[REQUEST_URI]";

answered Sep 06 '14 at 17:14

MH2K9

1

This does not work for https or different ports, also it does not contain the query string – MrTux Sep 06 '14 at 17:15

score 0 · Answer 2 · answered Sep 06 '14 at 17:18

0

look at $_SERVER array

print_r($_SERVER);

answered Sep 06 '14 at 17:18

Daniel Kucal

Joseph8th · Answer 3 · 2014-09-06T17:29:55.557

0

You can use the $_SERVER globals to get this info. $_SERVER["REQUEST_URI"] should give you new/id=2 and the full (GET) request URI.

ETA: My bad. MrTux is right... you need to concatenate $_SERVER["QUERY_STRING"] to get the URI and the query. So try this:

$uri_query = $_SERVER["REQUEST_URI"].$_SERVER["QUERY_STRING"];

edited Sep 06 '14 at 17:29

answered Sep 06 '14 at 17:19

Joseph8th

For a more complete implementation that solves MrTux's valid comment on user3659034's answer, see [this cheatsheet](http://webcheatsheet.com/php/get_current_page_url.php). – Joseph8th Sep 06 '14 at 17:21
You still might need to add a "?" before ```.$_SERVER["QUERY_STRING"]```. – MrTux Sep 06 '14 at 17:31

score 0 · Answer 4 · answered Sep 06 '14 at 17:27

Use the parse_url function of php.

$url = '//www.example.com/path?googleguy=googley';

$query=parse_url($url));

var_dump($query);

The above example will output

array(3) {
  ["host"]=>
  string(15) "www.example.com"
  ["path"]=>
  string(5) "/path"
  ["query"]=>
  string(17) "googleguy=googley"
}

That means you will get your required value at $query["query"]

score 0 · Answer 5 · edited Sep 03 '21 at 09:30

0

When you use print_r($_SERVER);, you get a peak into all the server details, including the page referrer, in $_SERVER['HTTP_REFERER'].

edited Sep 03 '21 at 09:30

apaderno

answered Sep 03 '21 at 06:48

Emmanuel Oraegbu

5 Answers5