How to print very large natural numbers in Python in non exponential form?

Question

The number can be very large

n = input()
print(n) #gives output in scientific notation

How to get the entire number?

PS: New to python

EDIT:

s = (input())      #100000000000000000000000000000000000000
if int(s[-1])%2 == 0:
    print (2)
    print (2)
    print (int(s)/2)         #5e+37

The question is unclear. Give an example of what "input" looks like and what the printout should look like — Anas Elghafari, Sep 07 '14 at 10:29

score 3 · Accepted Answer · answered Sep 07 '14 at 10:39

3

In Python 3, if you want integer division, use the // operator:

print(int(s) // 2)

The result of the division will be an integer and will not get printed out in the scientific notation.

answered Sep 07 '14 at 10:39

NPE

2

Note that `//` operator has been there [*since Python 2.2*](https://docs.python.org/3/whatsnew/2.2.html#pep-238-changing-the-division-operator). So it is the recommended way to obtain integer division since then (even on python2). Your wording may be interpreted as if `//` is only part of python3, and one should use `/` in python2. – Bakuriu Sep 07 '14 at 11:08

score 1 · Answer 2 · edited May 23 '17 at 10:26

1

You can format a large number into a scientific notation using the {:2E} formatting code. Example:

>>> "{:.2E}".format(100000000000000000000000000000000000000)
'1.00E+38'

Another variation to do this:

>>> n = 100000000000000000000000000000000000000
>>> '%2E' % n
'1.000000E+38'

See this question for discussion about the stripping out the extra zeros from the output.

edited May 23 '17 at 10:26

Community

answered Sep 08 '14 at 00:59

Anas Elghafari

2 Answers2