how to fetch a page link and get open it inside phone browser, on user click (Android)

Question

i wonder how to get address of a page inside of a web view on user click, and take that address and open it inside phone browser. for example let's say i open google inside a web view and when i click on one of the links from search then i want to fetch that link and get open it inside phone browser. the code for the web view is as follows:

myWebView = (WebView) findViewById(R.id.webView1);
    myWebView.setWebViewClient(new WebViewClient());         
    myWebView .getSettings().setJavaScriptEnabled(true);
    myWebView .getSettings().setDomStorageEnabled(true);
    myWebView.getSettings().setJavaScriptEnabled(true);
    myWebView.getSettings().setSupportZoom(false);
    myWebView.getSettings().setDomStorageEnabled(true);
    myWebView.getSettings().setBuiltInZoomControls(true);
    myWebView.loadUrl("http://www.google.com/");

Possible duplicate of http://stackoverflow.com/questions/2201917/how-can-i-open-a-url-in-androids-web-browser-from-my-application — Wagner DosAnjos, Sep 08 '14 at 19:53

score 0 · Answer 1 · edited May 23 '17 at 12:21

0

you can inject javascript that will find the link and call function from your java activity with android java bridge like How to call javascript from Android?

edited May 23 '17 at 12:21

Community

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answered Sep 08 '14 at 19:58

Noam Wies

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how to fetch a page link and get open it inside phone browser, on user click (Android)

1 Answers1