How to get week of the month when selecting a date in datetimepicker?

Question

I have a datetimepicker control in winform which I am creating in c#.

How would I get the week number of the month when I select a date in datetimepicker control in c#?

That means, If I select the date as 09/09/2014 then the result should be shown in next textbox control as 2nd week of the month in the winform.

Please help me out.

check this http://stackoverflow.com/questions/11154673/get-the-correct-week-number-of-a-given-date — V2Solutions - MS Team, Sep 10 '14 at 10:30
I have edited question ,,Will u please look over It @jbutler483 — Shiva Debrown, Sep 10 '14 at 10:41
@ShivaDebrown I would be happy enough with Sepehr's answer (it should work for you) — jbutler483, Sep 10 '14 at 10:46

Simon Farshid · Answer 1 · 2014-09-10T10:42:35.790

1

var month = datetimepicker.Value.Month;
var weekNumberThisMonth = (datetimepicker.Value.Day + (7 - (int)datetimepicker.Value.DayOfWeek)) / 7;

edited Sep 10 '14 at 10:42

answered Sep 10 '14 at 10:26

Simon Farshid

can't test this at present, but if it's the 1st of the month - won't this give it as 'Week 0'? – jbutler483 Sep 10 '14 at 10:44
I'm getting error at math.floor() @seepher farshid – Shiva Debrown Sep 10 '14 at 10:48
Not sure if that works now (again) - what happens if you pass in **10**? you'd get **10+(7-10)/7** == 10+(-3)/7 == 7/7 == 1 yet should be 2nd week? – jbutler483 Sep 10 '14 at 10:50
No! datetimepicker.Value.DayOfWeek is a number from 0 to 6! – Simon Farshid Sep 10 '14 at 10:51
1

So for today, it's 10 + (7 - 3 (Wednesday)) / 7 which is 14 / 7 = 2! – Simon Farshid Sep 10 '14 at 10:52

score 1 · Accepted Answer · answered Sep 10 '14 at 14:30

1

There is a simpler way to do this :

 private void dateTimePicker1_ValueChanged(object sender, EventArgs e)
{
   txtweek.Text=  (1+(dateTimePicker1.Value.Day / 7)).ToString("0");
}

answered Sep 10 '14 at 14:30

karim

Shiva Debrown · Answer 3 · 2014-09-20T06:42:27.067

0

txtweek.Text= (1+(dateTimePicker1.Value.Day / 7)).ToString("0");

This is my answer

edited Sep 20 '14 at 06:42

answered Sep 10 '14 at 11:01

Shiva Debrown

3 Answers3