PHP Date issues

Question

i have a question. I'm trying to figure out the answer to this question but i can't seem to wrap my mind around it. Hopefully someone can help me. The question is:

Write a function that takes someone's first name, last name, birth year, month and day as arguments and gives back the full name + age. Make sure that the app/programm also gives back the correct results in 2015 or later. Check if the first 2 arguments are strings and the thirds is an integer.

Since I am new to PHP and have no clue about dates (i googled but i can't get my mind wrapped around it) Thanks in advance! :) (wrote some code myself to try but it's useless so i left it out)

Answer 1

<?php
function getAge($f_name, $l_name, $b_day, $b_month, $b_year) {

  //date in mm/dd/yyyy format; or it can be in other formats as well
  $birthDate = $b_month . "/" . $b_day . "/" . $b_year;
  //explode the date to get month, day and year
  $birthDate = explode("/", $birthDate);
  //get age from date or birthdate
  $age = (date("md", date("U", mktime(0, 0, 0, $birthDate[0], $birthDate[1], $birthDate[2]))) > date("md")
    ? ((date("Y") - $birthDate[2]) - 1)
    : (date("Y") - $birthDate[2]));
  return $f_name ." ". $l_name ." is: " . $age;
}
?>

Answer 2

Here is a simple function to do that

//birthday YYYY-MM-DD
function userInfo($fname, $lname, $birthday) {
   //Calc age 
   $age = date_diff(date_create($birthday), date_create('today'))->y;  
   return $fname ." ". $lname . " ".$age;
}

now call it

echo userInfo('John', 'Doe', '1986-02-01');

Answer 3

use this function

<?php
    function get_the_user($fname, $lname,$m ,$d,$y)


      $birthDate =$m.'/'.$d.'/'.$y;
      //explode the date to get month, day and year
      $birthDate = explode("/", $birthDate);
      //get age from date or birthdate
      $age = (date("md", date("U", mktime(0, 0, 0, $birthDate[0], $birthDate[1], $birthDate[2]))) > date("md")
        ? ((date("Y") - $birthDate[2]) - 1)
        : (date("Y") - $birthDate[2]));
      echo "Age is:" . $age;
    return $fname.' '.$lname.'is '.$age.' old';
    ?>

Answer 4

You can use DateTime class for simple operations with datetimes.

function getAge($name, $surname, $b_year, $b_month, $b_date)
{
    $today = new DateTime();
    $birthdate = new DateTime($b_year . '-' . $b_month . '-' . $b_date);
    $diff = $today->diff($birthdate);

    return $name . ' ' . $surname . ' is ' . $diff->format('%y years') . ' old';
}

echo getAge('Mr.', 'Smith', 1990, 12, 12);

Output:

Mr. Smith is 23 years old

Live preview

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Check if the first 2 arguments are strings and the thirds is an integer.

I believe this won't be problem for you :).

Useful resources:

• http://php.net/manual/en/function.gettype.php
• http://php.net/manual/en/ref.var.php

Answer 5

Why not create a Person object and create some methods to handle the logic and formatting. Like:

class Person {

   public $firstName, $lastName, $dob;

   public function __construct($firstName, $lastName, $dob) {
      $this->firstName = $firstName;
      $this->lastName = $lastName;
      $this->dob = new DateTime($dob);
   }

   public function getFullname() {
      return $firstName . ' ' . $lastName;
   }

   public function getAge($onDate=null) {
      if ($onDate === null) $onDate = date('Y-m-d');
      $onDate = new DateTime($onDate);

      $ageOnDate = $this->dob->diff($onDate)->y;
      return $ageOnDate;
   }

}

$dude = new Person('John', 'Doe', '1980-01-15');
echo $dude->getFullName() . "\n";
echo $dude->getAge() . "\n"; // get his age today
echo $dude->getAge('2015-06-01'); // get his age on June 1st, 2015